n^2+18n-37=7

Solution for n^2+18n-37=7 equation:

n^2+18n-37=7

We move all terms to the left:

n^2+18n-37-(7)=0

We add all the numbers together, and all the variables

n^2+18n-44=0

a = 1; b = 18; c = -44;
Δ = b2-4ac
Δ = 182-4·1·(-44)
Δ = 500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{500}=\sqrt{100*5}=\sqrt{100}*\sqrt{5}=10\sqrt{5}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-10\sqrt{5}}{2*1}=\frac{-18-10\sqrt{5}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+10\sqrt{5}}{2*1}=\frac{-18+10\sqrt{5}}{2}
$